Integrand size = 24, antiderivative size = 106 \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=-\frac {\left (4-e^2 x^2\right )^{3/4}}{11 \sqrt [4]{3} e (2+e x)^{7/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{77 \sqrt [4]{3} e (2+e x)^{5/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{231 \sqrt [4]{3} e (2+e x)^{3/2}} \]
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Time = 0.03 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {673, 665} \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{231 \sqrt [4]{3} e (e x+2)^{3/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{77 \sqrt [4]{3} e (e x+2)^{5/2}}-\frac {\left (4-e^2 x^2\right )^{3/4}}{11 \sqrt [4]{3} e (e x+2)^{7/2}} \]
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Rule 665
Rule 673
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (4-e^2 x^2\right )^{3/4}}{11 \sqrt [4]{3} e (2+e x)^{7/2}}+\frac {2}{11} \int \frac {1}{(2+e x)^{5/2} \sqrt [4]{12-3 e^2 x^2}} \, dx \\ & = -\frac {\left (4-e^2 x^2\right )^{3/4}}{11 \sqrt [4]{3} e (2+e x)^{7/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{77 \sqrt [4]{3} e (2+e x)^{5/2}}+\frac {2}{77} \int \frac {1}{(2+e x)^{3/2} \sqrt [4]{12-3 e^2 x^2}} \, dx \\ & = -\frac {\left (4-e^2 x^2\right )^{3/4}}{11 \sqrt [4]{3} e (2+e x)^{7/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{77 \sqrt [4]{3} e (2+e x)^{5/2}}-\frac {2 \left (4-e^2 x^2\right )^{3/4}}{231 \sqrt [4]{3} e (2+e x)^{3/2}} \\ \end{align*}
Time = 0.62 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.46 \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=-\frac {\left (4-e^2 x^2\right )^{3/4} \left (41+14 e x+2 e^2 x^2\right )}{231 \sqrt [4]{3} e (2+e x)^{7/2}} \]
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Time = 2.23 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.42
method | result | size |
gosper | \(\frac {\left (e x -2\right ) \left (2 x^{2} e^{2}+14 e x +41\right )}{231 \left (e x +2\right )^{\frac {5}{2}} e \left (-3 x^{2} e^{2}+12\right )^{\frac {1}{4}}}\) | \(44\) |
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Time = 0.32 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.66 \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=-\frac {{\left (2 \, e^{2} x^{2} + 14 \, e x + 41\right )} {\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {3}{4}} \sqrt {e x + 2}}{693 \, {\left (e^{5} x^{4} + 8 \, e^{4} x^{3} + 24 \, e^{3} x^{2} + 32 \, e^{2} x + 16 \, e\right )}} \]
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\[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=\frac {3^{\frac {3}{4}} \int \frac {1}{e^{3} x^{3} \sqrt {e x + 2} \sqrt [4]{- e^{2} x^{2} + 4} + 6 e^{2} x^{2} \sqrt {e x + 2} \sqrt [4]{- e^{2} x^{2} + 4} + 12 e x \sqrt {e x + 2} \sqrt [4]{- e^{2} x^{2} + 4} + 8 \sqrt {e x + 2} \sqrt [4]{- e^{2} x^{2} + 4}}\, dx}{3} \]
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\[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=\int { \frac {1}{{\left (-3 \, e^{2} x^{2} + 12\right )}^{\frac {1}{4}} {\left (e x + 2\right )}^{\frac {7}{2}}} \,d x } \]
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Exception generated. \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=\text {Exception raised: TypeError} \]
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Time = 10.56 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.83 \[ \int \frac {1}{(2+e x)^{7/2} \sqrt [4]{12-3 e^2 x^2}} \, dx=-\frac {{\left (12-3\,e^2\,x^2\right )}^{3/4}\,\left (\frac {2\,x}{99\,e^3}+\frac {41}{693\,e^4}+\frac {2\,x^2}{693\,e^2}\right )}{\frac {8\,\sqrt {e\,x+2}}{e^3}+x^3\,\sqrt {e\,x+2}+\frac {12\,x\,\sqrt {e\,x+2}}{e^2}+\frac {6\,x^2\,\sqrt {e\,x+2}}{e}} \]
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